In a number system with base b,15*22=363 the value of b is
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15 = b + 5
22 = 2b + 5
363 = 3b² + 6b + 3
so (b+5) (2b+5) = 3b² + 6b + 3
2b² + 5b + 10b + 25 = 3b² + 6b + 3
3b² - 2b² + 6b - 15b + 3 - 25 = 0
b² - 9b - 22
(b+2)(b-11)
b = -2, 11
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