In a parallelogram ABCD, AB= 6 cm, AD= 5cm, and distance between longer sides is 4 cm. Find the distance between the shorter sides.
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Answer:
4.8 cm
Step-by-step explanation:
First we will draw a parallelogram ABCD
Opposite sides of parallelogram are equal
So AB = DC
So, DC = 6 cm
AD= BC
BC = 5cm
Draw a perpendicular from angle B which fall on AC
Name it as G
Now, BG will be the longer side
BG = 4 cm ( height)
So area of parallelogram = base ×height
= 6cm ×4cm
= 24 cm^2
Draw a perpendicular from angle D which will fall on BC
Name it as F
DF =? (height)
Let DF be x
Area of parallelogram = base ×height
24 cm^2 = 5cm × x
24 cm^2 /5 cm = x
X= 4.8 cm
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