in a parallelogram abcd, angelb=50 degree then what is the measure of all other angels
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Answered by
3
Hey there!
In parallelogram opposite angles are equal and sum of Adjacent angle = 180°
So B = D = 50°
We know that B+A = 180
A =180-50=130
A = C = 130°
So finally
Angle A = 130°
Angle B = 50°
Angle C = 130°
Angle D = 50°
hope helped!
In parallelogram opposite angles are equal and sum of Adjacent angle = 180°
So B = D = 50°
We know that B+A = 180
A =180-50=130
A = C = 130°
So finally
Angle A = 130°
Angle B = 50°
Angle C = 130°
Angle D = 50°
hope helped!
zaidbolter:
thanks a lot for helping me
Answered by
1
in parallelogram opposite angles are equal then <a = 50
and also in parallelogram sum of adjacent angles is 180
then angle c + angle b = 180
50+ angle c = 180
angle c = 130
thus angle d is also equal to 130
hence angles are 50,50,130,130
hope this answer helps u...
and also in parallelogram sum of adjacent angles is 180
then angle c + angle b = 180
50+ angle c = 180
angle c = 130
thus angle d is also equal to 130
hence angles are 50,50,130,130
hope this answer helps u...
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