Math, asked by romirk3964, 9 months ago

In a parallelogram ABCD, angle A=(3x-10), angle B=(5x+30) find all angles of parallelogram

Answers

Answered by sangeetasingh4380
1

Answer:

The angles are 130°,50°,130°,50°.

Answered by smritisharma2907
4

Step-by-step explanation:

ABCD is a parallelogram.

AngleA=AngleC ( opposite angles)

AngleD=AngleB (opposite angles)

Now, AngleA +AngleC=180degree

AngleD+angleC=180degree

(adjacant sides)

So,

Ang. (A+B+C+D) =360deg

2(3x-10)+2(5x+30)=360

16x+40=360

x=20deg

Hence,

Angle A=angC=50deg

AngleD=angB=130deg

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