Question

in a parallelogram abcd are the midpoints of sides ab and cd respectively.show that the line segment af and ce trisect the diagonal bd

Answer 1

af and ce trisect at bd
ap+pf=af
eq+qc=ec
bd=dp+pq+qb
proved

Answer 2

CD=AB
1/2CD=1/2AB
CF=AE
so AECF is a //gm.
PF//PQ-----eq1
AP//PQ-----eq2
AP//EQ......... 1/2in the fig....