Question

the resistance of a wire of length 300 m and cross _section area 1.0mm^2 made of material of resistivity 1.0×10^-7

Answer 1

given,
length of the wire L=300m
area of cross section A=1.0mm^2=1x10^-6m
resistivity (rho) =1.0x10^-7
Resistance R=rho (L/A)
R=1.0x10^-7x300/1.0x10^-6
R=300x10^-1
R=30 Ohm

Answer 2

The resistance of the wire is 30 ohms.

The resistance (R) of a wire can be calculated using the formula:

R = (ρ * L) / A

where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

Substituting the given values, we get:

$\frac{ 1.0*10^{2} -7*300}{1.0*10^{2} }$

Converting $1.0*10^{-7}$

$1.0mm^2 = (1.0/1000)^2 m^2 = 1.0*10^{-6} m^2$

Substituting this value, we get:

$R = (1.0*10^{-7} * 300) / (1.0*10x^{-6} )$

Simplifying the expression, we get:

R = 30 Ω

Therefore, the resistance of the wire is 30 ohms.

For similar questions on Resistance of wire

https://brainly.in/question/15380315

#SPJ3