in a parallelogram ABCD , E and F are points on AB and CD such that AE = CF prove that ED parallel to BF
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Hey, here is your answer mate!
Step-by-step explanation:
Given: ABCD is a parallelogram and AE = CF ...(1)
To Prove: EDBF
Proof:
Since the opposite sides of the parallelogram are equal.
AB = CD ... (2)
Subtract (1) from (2):
AB - AE = CD - CF
BE = DF ... (3)
Also, BE is parallel to DF, therefore BEDF is a parallelogram.
Thus ED is parallel to BF.
Hope you understood
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