Math, asked by princirajpoot, 1 year ago

in a parallelogram ABCD , E and F are points on AB and CD such that AE = CF prove that ED parallel to BF

Answers

Answered by sonammadhukar12
9
hope this will help you thank you
Attachments:
Answered by smjothibasu
0

Answer:

Hey, here is your answer mate!

Step-by-step explanation:

Given: ABCD is a parallelogram and AE = CF       ...(1)

To Prove: EDBF

Proof:

Since the opposite sides of the parallelogram are equal.

AB = CD         ... (2)

Subtract (1) from (2):

AB - AE = CD - CF

BE = DF      ... (3)

Also, BE is parallel to DF, therefore BEDF is a parallelogram.

Thus ED is parallel to BF.

Hope you understood

Similar questions