In a parallelogram ABCD SUM OF TWO ANGLES IS 130°WRITE THE MEASURE OF IT'S ACUTE ANGLE
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in a parallelogram sum of 2 angles is 130°
since , it is a parallelogram , the consecutive Angles cannot be 130° as their sum is 180°
therefore , the opposite angles of parallelogram are 130°
we know , sum of all angles of a quadrilateral is 360°
and let one acute angle be x
other acute angle = x (as opposite angles of parallelogram are equal)
so ,
130°+130°+x+x = 360°
=> 2x+260°= 360°
=> 2x = 100°
=> x = 100/2 => 50°
acute angle of parallelogram measures 50°
hope this helps
since , it is a parallelogram , the consecutive Angles cannot be 130° as their sum is 180°
therefore , the opposite angles of parallelogram are 130°
we know , sum of all angles of a quadrilateral is 360°
and let one acute angle be x
other acute angle = x (as opposite angles of parallelogram are equal)
so ,
130°+130°+x+x = 360°
=> 2x+260°= 360°
=> 2x = 100°
=> x = 100/2 => 50°
acute angle of parallelogram measures 50°
hope this helps
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