In a parallelogram KITE angle KIT = 75 KA is perpendicular on IT. KA and EI intersect atB where A is a point on IT. If EB=2KI then measure of angle KEB is
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In a parallelogram KITE angle KIT = 75 KA is perpendicular on IT. KA and EI intersect atB where A is a point on IT. If EB=2KI then measure of angle K
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KA ^ IT
Ð I = 75° Ð AKI = 15°
KE || IT
\ ÐAKE = 90°
Let D be the mid point of EB
Since in a right angled D, mid point of the hypotenuse is
equidistant from the vertices
\ DK = DB = DE Let ÐABI = q= ÐDKB = q
17
In DDKB, ÐBDK = 180° – 2q
In DIKD
IK = KD
\ ÐKID = ÐKDI = 180–2q
In DIKD, 180° – 2q+ 180° – 2q+ q+ 15° = 180°
\ 180° + 15° = 4q– q
195° = 3q
65° = q
ÐABI = 65°
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