in a parallelogram one angle 2 by 3 of its adjacent angle find all the angles of the parallelogram
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Answer:
The angles of the parallelogram are 108, 72, 108, 72
Step-by-step explanation:
let one pf the angles of the parallelogram be x
the adjacent angle of x, given is 2/3 of x which is equal to 2x/3
in a parallelogram opposite angles are equal
therefore,
the angles of the parallelogram are x, 2x/3, x, 2x/3
in a parallelogram sum of all the angles of the parallelogram is equal to 360 degrees
therefore,
x + 2x/3 + x + 2x/3 = 360
2x + 4x/3 = 360
(6x+4x)/3 = 360
10x/3 = 360
10x = 360 * 3
x = 360*3 / 10
x = 108
2x/3 = 2 * 108 /3
2x/3 = 72
therefore the angles of the parallelogram are 108, 72, 108 and 72
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