Question

In a parallelogram out of the two adjacent angels, one angle is greater than the other by 20°. Find the measure of all the angels.
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Answer 1

Let one angle = x + 20°

Let the another angle = x

In parallelogram opposite angle are equal,

In parallelogram adjacent angles are supplementary,

Angle sum property of a parallelogram

= 360°

x + 20 + x + 20 + x + x = 360

=> 4x + 40 = 360

=> 4x = 360 - 40

=> 4x = 320

=> x = 320/4

=> x = 80

Angles are 80°,80°,

then x + 20 = 80 + 20 = 100°, 100°

Answer 2

Step-by-step explanation:

A parallelogram is a tilted version of rectangle. ABCD is a parallelogram then we can say that if we it as a rectangle then all angles are right.

<A=<B=<C=<D=90°

But if it is a parallelogram then we can add 10° to <A and <C and subtract 10° from <B and <D

<A= 90°-10°=80°

<B=90°+ 10°=100°

<C= 90°-10°=80°

<D=90°+ 10°=100°

Total Sum

=<A+<B+<C+<D

=80°+100°+80°+100°

=360°

So if we subtract in each case we will get 20° or -20°

<A-<B=80°-100°= -20°

<B-<C=100°-80°=20°

<C-<D=80°-100°= -20°

<D-<A=100°-80°=20°

Hope will help you

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