Physics, asked by vishagh, 1 year ago

In a potentiometer arrangement a cell of emf 1.25v gives a balance point at 35cm of wire.if the cell is replaced by another cell and balance point shift to 63.0cm.what is the emf of second cell.

Answers

Answered by Paris11
21
here is the equation we use in tje case of potentiometer Ex/Es=Lx/Ls
here Ex=unkown emf of x cell ?
Lx= known length of unkown emf =63cm
Es=standard cell emf = 1.25
Ls= length of standard emf = 35cm
on arranging Ex=63/35×1.25 = which happens to be 2.25
let me know if its wrong thnx
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