In a potentiometer arrangement a cell of emf 1.25v gives a balance point at 35cm of wire.if the cell is replaced by another cell and balance point shift to 63.0cm.what is the emf of second cell.
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here is the equation we use in tje case of potentiometer Ex/Es=Lx/Ls
here Ex=unkown emf of x cell ?
Lx= known length of unkown emf =63cm
Es=standard cell emf = 1.25
Ls= length of standard emf = 35cm
on arranging Ex=63/35×1.25 = which happens to be 2.25
let me know if its wrong thnx
here Ex=unkown emf of x cell ?
Lx= known length of unkown emf =63cm
Es=standard cell emf = 1.25
Ls= length of standard emf = 35cm
on arranging Ex=63/35×1.25 = which happens to be 2.25
let me know if its wrong thnx
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