in a quadrilateral ABCD, /_B=90degree. if AD^2=AB^2+BC^2+CD^2,prove that /_ACD=90degree
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see the detail my friend it is explained in the photo
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Sampurnaghosal:
thank you very much
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I draw an imaginary picture of this quadrilateral, then from triangle ABC, I got pythagorus theorem, then from the given clue I used it, then I got AD^2=AC^2 +CD^2 which indicates that triangle ACD is a right angle where angle C is 90°
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