Question

in a reaction,R to Products,the concentration of reactant is doubled, the rate of reaction remains same, what is the order of the reaction

Answer 1

It's a zero order reaction.

Answer 2

Answer: The order of the reaction is zero.

Explanation:

$R\rightarrow Products$

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$Rate=k[R]^x$     (1)

x= order

On doubling the concentration of reactants, i.e [R]

New rate = $Rate'=k[2R]^x$    (2)

Dividing 2 by 1 :$\frac{Rate'}{Rate}=\frac{k\times [2R]^x}{k\times [R]^x}$

Given: Rate'= Rate

$1=2^x$

$2^0=2^x$

therefore x=0.

The order of the reaction is zero.