Question

In a rectangle ABCD, AB = 4 cm and BC = 3 cm. Find the length of the diagonals AC and BD.

Answer 1

Answer:

AC = 5cm, BD = 5cm

Step-by-step explanation:

Given : AB = 4cm, BC = 3cm

As it is a triangle so,

AB=CD (4cm) and BC =AD (3cm)

For triangle ABC

By using Pythagoras theorem :

AC² = AB² + BC²

AC² = 4² + 3²

AC²= 16 + 9

AC²= 25

AC = 5cm

Again,

For triangle ADB

By using Pythagoras theorem,

BD²= AB²+AD²

BD²= 4²+3²

BD²= 16+9

BD²= 25

BD = 5cm

Hope u will understand

Answer 2

Given:

Length of side AB = 4 cm

Length of side BC = 3 cm

To find:

The length of the diagonals.

Solution:

We know that a rectangle has a right angle, thus we can apply the Pythagoras theorem in this case:

AB²+BC²=AC²

On substituting the values in the given equation, we get:

4²+3²=AC²

On simplifying we get:

16+9=AC²

AC²=25

On solving further, we get:

AC=5 cm

Since both the diagonals will have the same length, hence the length of both diagonals AC and BD will be 5 cm.