Question

in a rectangle ABCD, angle BAC is equal to 32 find the measure of angle DBC

Answer 1

Answer:

MARK THE P WHERE THE DIAGONALS INTERSECT.

Angle BAC = 32 degree

BAC + DAC = 90 degree

32 + DAC = 90

DAC = 90-32

        =58

angle DAC =BCA= 58

BPC = 90

BPC + DBC + BCA = 180

90 + DBC + 58 = 180

DBC = 180- (90 + 58)

DBC = 180 - 148

DBC = 32