Question

In a rhombus abcd, angle ac and cd is teta such that cos(teta)=2/3. If the diagonals of the rhombus intersect each other at p such that dp=4cm, then find the length of sides and diagonals of the rhombus.

Answer 1

Answer:

Hey guys

Step-by-step explanation:

If we draw a figure with the given conditions,(Please refer figure in video)

OBAB=sinθ

Given that OB=8cm and cosθ=0.6

8AB=1−cos2θ−−−−−−−−√

AB=80.8=10cm

Also,AOAB=cosθ=0.6

AO=6cm

So, diagonal AC=6∗2=12cm

Similarly, diagonal BD=2∗OB=16cm.

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