In a Rhombus ABCD ,diagonals AC And BD intersect each other at O . if Angle ABC =72 thn find angle ACD
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1
one hundred forty four
lalu4:
i want to know the explanation....
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In rhombus
1) sum of adjacent angles are supplementary(180 degrees)
72+2)diagonal AC bisects the angle BCD
Therefore
=108/2
=54
1) sum of adjacent angles are supplementary(180 degrees)
72+2)diagonal AC bisects the angle BCD
Therefore
=108/2
=54
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