Question

In a rhombus ABCD, the diagonals intersect each other at O. If angle A= 60°and OA= 2cm, then the side of the rhombus is?​

Answer 1

Answer:

Step-by-step explanation:

i  think you mean that the angles are A, B, C, D. For a rhombus, the diagonals intersect at right angles, like in a square (necessary because of the 4-fold symmetry of rhombuses and squares). The diagonals bisect the angles, so the angle at A is bisected by the diagonal, so the angle OAB is 30°, and the angle at O is 90°. If the distance OA is 2 cm, then solving the right-angled triangle using simple trig gives the side length as 2 / cos 30° = 4 / sort(3) = 2.309 cm. The distance OB = 1.155 cm, and that gives you everything needed for drawing/defining the rhombus.

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