Question

In a right angle triangle ABC with right angle at B, in which a= 24 units, b= 25 units and
BAC = 0. Then, find cos 0 and tan e.​

Answer 1

Answer:

Given that,

in right angle triangle

b=25 units,a=24units

angle ABC=90, angle BAC=theta

By above we get,

AC=hypotenuse=25 units

BC=side opposite to angle theta=24units

By applying Pythagoras theorem we get

AB=side adjacent to angle theta=7 units

Now we have,

cos(theta)=side adjacent to angle theta/hypotenuse

cos(theta)=7/25

tan(theta)=side opposite to angle theta/side adjacent to angle theta

tan(theta)=24/7

Hence cos(theta)=7/25

and tan(theta)=24/25

Answer 2

Given that,

in right angle triangle

b=25 units,a=24units

angle ABC=90, angle BAC=theta

By above we get,

AC=hypotenuse=25 units

BC=side opposite to angle theta=24units

By applying Pythagoras theorem we get

AB=side adjacent to angle theta=7 units

Now we have,

cos(theta)=side adjacent to angle theta/hypotenuse

cos(theta)=7/25

tan(theta)=side opposite to angle theta/side adjacent to angle theta

tan(theta)=24/7

Hence cos(theta)=7/25

and tan(theta)=24/7