in a right angled if hypotenus is 14 then find its median on hypotenuse
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In ∆ABC
angle ABC=90°
set BD is perpendicular to hypo DE
By property of Geometric mean corollary
BD^2 =AD×DC
therefore BD^2=7×7. [since BD us the median]
therefore BD^ 2= 49
therefore BD = 7cm
angle ABC=90°
set BD is perpendicular to hypo DE
By property of Geometric mean corollary
BD^2 =AD×DC
therefore BD^2=7×7. [since BD us the median]
therefore BD^ 2= 49
therefore BD = 7cm
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