in a right angled isosceles triangle.if its sides are increased by 75%,then the percentage change its areas?
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Solution :-
In an isosceles triangle, there are two sides with equal length.
Let the two sides with equal length of the original triangle before the increase be a and b and their length is 10 cm each.
Area of an isosceles triangle = 1/2*base*height
⇒ 1/2*10*10
⇒ 100/2
⇒ 50 cm²
Now, length of each of these two sides after the increase = 17.5 cm
Increased area = 1/2*17.5*17.5
⇒ 306.25/2
⇒ 153.125 cm²
Percentage increase in area = (Change in area*100)/ Original area
⇒ [(153.125 - 50)*100]/50
⇒ (103.125*100)/50
⇒ 10312.5/50
⇒ 206.25 %
So, if the sides are increased by 75 %, then the area will increase by 206.25 %.
Answer.
In an isosceles triangle, there are two sides with equal length.
Let the two sides with equal length of the original triangle before the increase be a and b and their length is 10 cm each.
Area of an isosceles triangle = 1/2*base*height
⇒ 1/2*10*10
⇒ 100/2
⇒ 50 cm²
Now, length of each of these two sides after the increase = 17.5 cm
Increased area = 1/2*17.5*17.5
⇒ 306.25/2
⇒ 153.125 cm²
Percentage increase in area = (Change in area*100)/ Original area
⇒ [(153.125 - 50)*100]/50
⇒ (103.125*100)/50
⇒ 10312.5/50
⇒ 206.25 %
So, if the sides are increased by 75 %, then the area will increase by 206.25 %.
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