Prove that the points (3,0) ,(6,4) and (-1,3) are the vertices of a right angle issocles triangle
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Vertices of the triangle are A(-3, 0), B(1, -3), C(4, 1)
Distance between two points = (x2 - x1)2+(y2 - y1)2
AB = √[(1 + 3)2 + (-3 -0)2] = 5
BC = √[(4 - 1)2 + (1 + 3)2] = 5
AC = √[(4 + 3)2 + (1 -0)2] = 50 = 52
AB = BC
Therefore, ΔABC is an isosceles triangle.
Distance between two points = (x2 - x1)2+(y2 - y1)2
AB = √[(1 + 3)2 + (-3 -0)2] = 5
BC = √[(4 - 1)2 + (1 + 3)2] = 5
AC = √[(4 + 3)2 + (1 -0)2] = 50 = 52
AB = BC
Therefore, ΔABC is an isosceles triangle.
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