Question

In a right angled triangle ABC AC is the hypotenuse and the other two sides are of the lengths 12M and 9m. X is a point outside the triangle such that XA =20m and XC=25m . Find the measure of angle XAC?

Answer 1

AC^2 = 12^2 + 9^2 AC^2 = 225 AC= 15

Now in triangle XAC AC = 15 XA =20 XC = 25

15^2 + 20^2 = 200 + 400 = 625 

So , 15^2 + 20^2 = 25^2 

Hence the opposite angle at 90 ....

Please mark it as brainiest answer ........

Answer 2

first use pythagorus theorm in triangle abc. 
ac^2 = 122^ + 9^2 
ac^2 = 225 
ac = 15 cm
now in triangle xac 
ac = 15    xa = 20   and xc = 25 
and we know that , 
15^2 + 20^2 = 225 + 400 = 625
so, 15^2 + 20^2 = 25^2 
hence triangle xac is a right angled triangle.
in xac xc is hypotenuse as it is the largest side
hence , angle opposite to hypotenuse in a right angle 
angle xac = 90