In a right angled triangle ABC AC is the hypotenuse and the other two sides are of the lengths 12M and 9m. X is a point outside the triangle such that XA =20m and XC=25m . Find the measure of angle XAC?
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AC^2 = 12^2 + 9^2 AC^2 = 225 AC= 15
Now in triangle XAC AC = 15 XA =20 XC = 25
15^2 + 20^2 = 200 + 400 = 625
So , 15^2 + 20^2 = 25^2
Hence the opposite angle at 90 ....
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Now in triangle XAC AC = 15 XA =20 XC = 25
15^2 + 20^2 = 200 + 400 = 625
So , 15^2 + 20^2 = 25^2
Hence the opposite angle at 90 ....
Please mark it as brainiest answer ........
Answered by
10
first use pythagorus theorm in triangle abc.
ac^2 = 122^ + 9^2
ac^2 = 225
ac = 15 cm
now in triangle xac
ac = 15 xa = 20 and xc = 25
and we know that ,
15^2 + 20^2 = 225 + 400 = 625
so, 15^2 + 20^2 = 25^2
hence triangle xac is a right angled triangle.
in xac xc is hypotenuse as it is the largest side
hence , angle opposite to hypotenuse in a right angle
angle xac = 90
ac^2 = 122^ + 9^2
ac^2 = 225
ac = 15 cm
now in triangle xac
ac = 15 xa = 20 and xc = 25
and we know that ,
15^2 + 20^2 = 225 + 400 = 625
so, 15^2 + 20^2 = 25^2
hence triangle xac is a right angled triangle.
in xac xc is hypotenuse as it is the largest side
hence , angle opposite to hypotenuse in a right angle
angle xac = 90
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