in a right angled triangle if the square of hypotenuse is twice the product of other two sides then one of the angles of the triangle is?
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Let the three sides of triangle are base(x), perpendicular(y) and hypotenuse(z)
then according to the given condition z^2 = 2x*y
or x^2 + y^2 = 2x*y
or (x-y)^2 = 0
or x = y
so triangle is isosceles and angle = 45 , 45 and 90
then according to the given condition z^2 = 2x*y
or x^2 + y^2 = 2x*y
or (x-y)^2 = 0
or x = y
so triangle is isosceles and angle = 45 , 45 and 90
Answered by
42
Answer:
One angle of the two angles of the right angle triangle is 45°
Step-by-step explanation:
In a right angle triangle, square of hypotenuse is twice the product of other two sides.
Therefore, h² = 2xy ------(1)
From Pythagoras theorem,
x² + y² = h²------(2)
From equation (1) and equation (2),
x² + y² = 2xy
x² + y² - 2xy = 0
(x - y)² = 0
x - y = 0
x = y
Both the sides of the right angle triangle are equal.
In ΔABC angles opposite to these sides will be equal.
We know sum of all angles in a right angle triangle is 180°
Therefore, m∠A + m∠B + m∠C = 180°
m∠A + 90° + m∠C = 180°
2(m∠A) = 180 - 90 = 90° [Since ∠A ≅ ∠C]
m∠A = 45°
Therefore, one angle of the triangle is 45°.
Learn more about the properties of the triangle from https://brainly.in/question/2383861
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