In a right angled triangle one acute angle is double the other. Prove that the hypotenuse is double the smallest side.
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The sum of the angles of a triangle is 180 degrees. When you take away 90 degrees you are left with 90 degrees.
So the other angles are 30 degrees and 60 degrees.
Since sin(30 degrees) = (1/2), and sin(x) = the length of the side opposite it divided by the length of the hypotenuse, then that side is (1/2) the size of the hypotenuse. That means that the hypotenuse is twice as long the side opposite the 30 degree angle.
So the other angles are 30 degrees and 60 degrees.
Since sin(30 degrees) = (1/2), and sin(x) = the length of the side opposite it divided by the length of the hypotenuse, then that side is (1/2) the size of the hypotenuse. That means that the hypotenuse is twice as long the side opposite the 30 degree angle.
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