Question

in a right triangle ABC, at right angled at B, n^2 tan A = 4/3 , then find tan C??
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Answer 1

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If ABC is right angle triangle then ,B =90°

then , tanA = 1/cotA

and tanA = 1/tanC

then
tanA = 4/3n²

then tanC = 3n²/4



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Answer 2

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HOPE THIS HELPS YOU ...

Answer:
If ABC is right angle triangle then ,B =90°
then B not equal to 90°

then , tanA = 1/cotA

and tanA = 1/tanC

Step-by-step Explanation:-
Using above mentioned formulas,

tanA = 4/3n²

Hence,
tanC = 3n²/4






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