Question

In a right triangle abc right angled at b bc equal to 12 cm and a b equal to 5 cm the radius of the circle inscribed in the triangle is

Answer 1

2cm is the answer kid

Answer 2

$\sf\red{PR=\sqrt{ {PQ}^{2} + {QR}^{2} } }$

$\longrightarrow$$\sf\red{\sqrt{ {12}^{2} + {5}^{2} }}$

$\longrightarrow$$\sf\red{13cm}$

$\sf\green{Area\:(∆ABC)=\frac{1}{2}×PQ×QR}$

$\sf\green{\frac{1}{2}×12×5={30cm}^{2}}$

$\sf\green{s=\frac{12+5+13}{2}=15cm}$

$\therefore$ $\sf{Inradius(r)=\frac{∆}{s}=\frac{30}{15}}$

$\longrightarrow$$\sf{2cm}$