Math, asked by rrnairsa4741, 1 year ago

in a right triangle ABC right angled at B , if P and Q are points on the sides AB and AC respectively , then -

a. AQ2 + CP2 = 2 ( AC2 + PQ2 )

b. 2 (AQ2 +CP2 ) = AC2 +PQ2

c. AQ2+ CP2 = AC2 + PQ2

d. AQ+ CP = 1/2 (AC+PQ)

PLZ ANSWER....AND ALSO GIV DE REASON...WHY?

PLZZZ

Answers

Answered by NidhraNair
70
hello ☺



ᴛʜᴇ ᴄᴏʀʀᴇᴄᴛ ᴀɴsᴡᴇʀ ɪs 'ᴄ'

ᴀǫ2+ᴄᴘ2=ᴀᴄ2 +ᴘǫ2


   ᴀǫ2 = ᴀʙ2 + ʙǫ2                            (1)

ᴄᴘ2= ᴄʙ2 + ʙᴘ2                                (2)

 
sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs

ᴀʙ2 + ʙǫ2 + ᴄʙ2 + ʙᴘ2 = ᴀᴄ2 + ᴘǫ2

ᴀʙ2 + ᴄʙ2 + ʙǫ2 + ʙᴘ2 = ᴀᴄ2 + ᴘǫ2

(ᴀʙ2+ᴄʙ2=ᴀᴄ2 ᴀɴᴅ ʙǫ2+ʙᴘ2=ᴘǫ2)

thank you ☺ ♥

NidhraNair: :)
Answered by Ashi03
12
Option C AQ2+ CP2 = AC2 + PQ2

HOPE IT HELPS ✌
Similar questions