in a right triangle ABC right angled at B , if P and Q are points on the sides AB and AC respectively , then -
a. AQ2 + CP2 = 2 ( AC2 + PQ2 )
b. 2 (AQ2 +CP2 ) = AC2 +PQ2
c. AQ2+ CP2 = AC2 + PQ2
d. AQ+ CP = 1/2 (AC+PQ)
PLZ ANSWER....AND ALSO GIV DE REASON...WHY?
PLZZZ
Answers
Answered by
70
hello ☺
ᴛʜᴇ ᴄᴏʀʀᴇᴄᴛ ᴀɴsᴡᴇʀ ɪs 'ᴄ'
ᴀǫ2+ᴄᴘ2=ᴀᴄ2 +ᴘǫ2
ᴀǫ2 = ᴀʙ2 + ʙǫ2 (1)
ᴄᴘ2= ᴄʙ2 + ʙᴘ2 (2)
sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs
ᴀʙ2 + ʙǫ2 + ᴄʙ2 + ʙᴘ2 = ᴀᴄ2 + ᴘǫ2
ᴀʙ2 + ᴄʙ2 + ʙǫ2 + ʙᴘ2 = ᴀᴄ2 + ᴘǫ2
(ᴀʙ2+ᴄʙ2=ᴀᴄ2 ᴀɴᴅ ʙǫ2+ʙᴘ2=ᴘǫ2)
thank you ☺ ♥
ᴛʜᴇ ᴄᴏʀʀᴇᴄᴛ ᴀɴsᴡᴇʀ ɪs 'ᴄ'
ᴀǫ2+ᴄᴘ2=ᴀᴄ2 +ᴘǫ2
ᴀǫ2 = ᴀʙ2 + ʙǫ2 (1)
ᴄᴘ2= ᴄʙ2 + ʙᴘ2 (2)
sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs
ᴀʙ2 + ʙǫ2 + ᴄʙ2 + ʙᴘ2 = ᴀᴄ2 + ᴘǫ2
ᴀʙ2 + ᴄʙ2 + ʙǫ2 + ʙᴘ2 = ᴀᴄ2 + ᴘǫ2
(ᴀʙ2+ᴄʙ2=ᴀᴄ2 ᴀɴᴅ ʙǫ2+ʙᴘ2=ᴘǫ2)
thank you ☺ ♥
NidhraNair:
:)
Answered by
12
Option C AQ2+ CP2 = AC2 + PQ2
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