in a room,a tubelight of 40W a fan of 75 W and a cooler 150W have been installed. If all these appliances are used for 8 hours a day calculate the energy consumed per
day
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Answered by
1
First, total power=40+75+150W=265W.
these are for one hour, then for 8 hours=265×8=2120.
therefore energy consumed per day(8 hrs) =2120 KWH
these are for one hour, then for 8 hours=265×8=2120.
therefore energy consumed per day(8 hrs) =2120 KWH
Answered by
0
Total power consumed = 40 + 75 + 150 = 265 W.
Energy consumed= (265×8)÷1000 = 2.12 KWh
Energy consumed= (265×8)÷1000 = 2.12 KWh
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