Question

In a school, maximum strength of each class is 60. In class
num strength of each class is 60 in class VIII. then total number of students is a
multiple of 5. On a certain day. four boys were absent
and the ratio of the numbers of the boys to that of girls was 5:4. Find the ratio of the total boys to that of girls.
​

Answer 1

Answer:

5:6

Step-by-step explanation:

i find by finding the remaining number of girls .

Answer 2

Given:

Maximum strength of each class in a school = 60

The strength of class VIII is a multiple of 5

On a certain day, 4 boys are absent and the ratio of the remaining boys to of the girls was 5:4

To find:

The ratio of the total boys to that of girls.

Solution:

Since it is given that the strength of class VIII is a multiple of 5

So, lets assume the strength of the class VIII to be the maximum possible strength of the school i.e., 60.

4 of the boys are absent

∴ The strength of the class VIII when the 4 boys are absent = 60 - 4 = 56

Also, the day when 4 boys were absent, the ratio of the remaining boys to that of the girls becomes 5:4.

So, let "5x" be the remaining no. of boys and "4x" be the no. of girls.

Therefore, we have an equation as,

5x + 4x = 56

⇒ 9x = 56

⇒ x = $\frac{56}{9}$

∴ Total no. of boys will be = 5x + 4 = $[5*\frac{56}{9}] + 4$ = $\frac{280 + 36}{9} = \frac{316}{9}$

and

∴ Total no. of girls will be = 4x = $4 * \frac{56}{9} = \frac{224}{9}$

Now,

The ratio of the total no. of boys to that of the girls is,

= $\frac{\frac{316}{9}}{\frac{224}{9}}$

= $\frac{316}{224}$

reducing both the numerator and denominator by dividing it by 2

= $\frac{79}{56}$

∵ $\frac{79}{56}$ = 1.4107, so rounding it to the nearest and simplest ratio

≈ $\frac{3}{2}$

Thus, the ratio of the total boys to that of girls is 3:2.

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