Question

In a school year of 196 days, wasim was absent for 14 days.What percentage of days was he present​

Answer 1

Answer:

196-14=182 %

Therefore percentage of days was he present=181

Answer 2

Given :-

• In a school year of 196 days, Wasim was absent for 14 days

Aim :-

• To find the percentage of days he was absent

Answer :-

Method 1 :-

By finding the percentage of days he was present and subtracting it from the total :-

$\begin{gathered}\boxed{\begin{array}{c|c} \bf Total \: \: percentage & \bf \:Number \: of \: days \: attended \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 100\% & \sf 196 \\ \\ \sf x\% & \sf 196 - 14 \end{array}} \\ \end{gathered}$

$\begin{gathered}\boxed{\begin{array}{c|c} \bf Total \: \: percentage & \bf \:Number \: of \: days \: attended \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 100\% & \sf 196 \\ \\ \sf x\% & \sf 182 \end{array}} \\ \end{gathered}$

Both the values are in direct proportion.

Hence, by cross multiplication,

$\implies \sf 182 \times 100 = 196 \times x$

Transposing 196,

$\implies \sf \dfrac{182 \times 100}{196} = x$

Reducing to the lowest terms,

$\implies \sf \cfrac{13 \times 50}{7} = x$

$\implies \sf \dfrac{650}{7} = x$

Therefore Wasim did attend 650/7% of days

Method 2 :-

$\longrightarrow \sf percentage \: not \: attended = \dfrac{number \: of \: days \: absent}{total \: number \: of \: days} \times 100$

• Number of days not attended = 14
• Total number of days = 196

Substituting,

$\implies \sf \dfrac{14}{196} \times 100$

Reducing to the lowest terms, we get :-

$\implies \sf \dfrac{50}{7} \%$

Number of days Wasim attended :-

$\longrightarrow \sf total \: percentage - percentage \: not \: attended$

Substituting,

$\implies \sf 100\% - \dfrac{50}{7} \%$

Taking LCM = 7,

$\implies \sf \dfrac{700 - 50}{7} \%$

$\implies \sf \dfrac{650}{7} \%$

Hence Wasim was present for 650/7% of the total number of school days