Question

In a simultaneous throw of two dice what is the probability of getting a total of 7

Answer 1

the no whose sum is 7 are
(1,6) (2,5) (3,4) (4,3) (5,2) (6,1)
therefore the probability of getting sum 7 = 6/36
                                                                 =1/6

Answer 2

favorable outcome ( the no. whose sum is 7 )

(1,6) (2,5) (3,4) (4,3) (5,2) (6,2)

total outcome=36

probability = favorable outcome/ total outcome

= 6/36

= 1/6

thanks dear❤️❤️❤️