Question

In a single throw of three dice, find the probability of getting a total greater than 8.​

Answer 1

Step-by-step explanation:

Simple space =6×6×6=216

Total outcomes =216

(i)Total of 5

a+b+c=5

(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)

∴ probability =2166=361

(ii) Atotal of atmost  5=(1,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1),(1,1,2),(2,1,1),(1,2,1) 

∴ prob =21610=1085

(iii)Probability of getting atleast 5=P(5)−P(<5)

=1−2164=216212=5453

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Answer 2

Step-by-step explanation:

mujhe jaanti ho kya bio main batao