Question

in a single throw of two die,
Find the probability that neither a
doublets nor a total of 10 will appear.
​

Answer 1

the qn is incorrect, it should be " when we throw a die twice or when two die are tossed together"..

Answer 2

Possible outcomes are:

(1,2);(1,3);(1,4);(1,5);(1,6);

(2,1);(2,3);(2,5);(2,5);(2,6);

(3,1);(3,2);(3,4);(3,5);(3,6);

(4,1);(4,2);(4,3);(4,5);

(5,1);(5,2);(5,3);(5,4);

(6,1);(6,2);(6,3):

No. of possible outcomes is 36

No. of favourable outcomes is 26

Probability

= 26/36

=13/18