Question

In a transformer the number of turns

of primary coil and secondary coil are

5 and 4 respectively. If 240 V is

applied to the primary coil, the ratio

of current in primary coil and

secondary coil is what​

Answer 1

$\large\underline{\underline{\sf Given:}}$

• Number of turn in primary coil $\sf{(N_p)}$= 5

• Number of turn in secondary coil $\sf{(N_s)}$ = 4

• Voltage applied on primary coil $\sf{(V_p)}$ = 240V

$\large\underline{\underline{\sf To\:Find:}}$

• Ratio of current in primary coil and secondary coil $\sf{\dfrac{I_p}{I_s}}$ = ?

$\large\underline{\underline{\sf Solution:}}$

As we know ,

$\large{\boxed{\sf r=\frac{N_s}{N_p} }}$

Here ,

r = ratio

•°•

$\large\implies{\sf r=\dfrac{4}{5}}$

Now ,

$\large{\boxed{\sf \frac{I_p}{I_s}=r }}$

$\large\implies{\sf \dfrac{I_p}{I_s}=\frac{4}{5}}$

$\large\implies{\sf I_p:I_s=4:5 }$

$\Large\underline{\underline{\sf Answer:}}$

•°•Ratio of Primary Current and Secondary current is 4:5 .