in a trapezium one of parallel side is more than 2cm of other parallel side and height is 8cm.Area is 80sq.cm then parallel sides are
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smaller side is 9cm and larger side is 11cm
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Let the smaller side be xcm and other be x+ 2 cm
as we know that
area of trapezium = 1/2 × sum of measure of parallel sides × height
80 = 1/2 ( x + x + 2 ) × 8
80 = 4 ( 2x + 2 )
80 = 8x + 8
8x = 80 - 8
x = 72/8
x = 9
so the parallel sides of trapezium are of 9 cm & 11 cm
as we know that
area of trapezium = 1/2 × sum of measure of parallel sides × height
80 = 1/2 ( x + x + 2 ) × 8
80 = 4 ( 2x + 2 )
80 = 8x + 8
8x = 80 - 8
x = 72/8
x = 9
so the parallel sides of trapezium are of 9 cm & 11 cm
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