In a triangle ABC, angle A+B=65°and angle b+c = 140 find the value of angle b and c
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Thus in abc
A + b = 65
B + c = 140
Thus by asp
A + b + c = 180
65 - b + b + 140 - b = 180
B = 25
Thus c = 140 - 25
. c = 115
A + b = 65
B + c = 140
Thus by asp
A + b + c = 180
65 - b + b + 140 - b = 180
B = 25
Thus c = 140 - 25
. c = 115
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