Question

In a triangle ABC, angle BAC = 90 , AD perpendicular to BC and BD=3 cm , CD= 4 cm than find AD

Answer 1

by given,
BD=3 cm
CD=4 cm
BY similarity criterion,
ΔBAC≈ΔBAD
Thus,$\frac{BC}{BA} = \frac{BA}{AD}$
SO,7AD=BA²-----------------------(1)
SImilarly,ΔDAC≈ΔBAC
Thus,$\frac{BA}{AD}= \frac{BC}{AC}$
SO,7AD=4BA
that gives BA=4cm
thus 7AD=4x4=16cm
AD=16/7=2.3cm