In a triangle ABC, D is a mid-point of BC; AD is produced upto E so that DE = AD.
Prove that triangle ABD and triangle ECD are congruent
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AD=DE(given)
BD=DC(midpoint)
angleADB=angleCDE(vertically opposite angles)
therefore triangle ABD is congruent to triangle ECD(S.A.S)
BD=DC(midpoint)
angleADB=angleCDE(vertically opposite angles)
therefore triangle ABD is congruent to triangle ECD(S.A.S)
anilkrmishranbp1ttbw:
please explain with answer
sorry
please explain with diagram
AD=DE is already given in the question
since D is the midpoint of BC,BD will be equal to CD
and angle ADB=angle CDE, because they are vertically opposite
sorry i cant add a pic
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