In a triangle ABC , DE is parallel yo BC . if AD =5 cm , DB =7cm and AC =18 cm . find the length of AE and EC
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Given :-a triangle ABC , DE is parallel to BC . if AD =5 cm , DB =7cm and AC =18 cm
To Find :-
find the length of AE and EC
Solution :-
since,abc & ade are similar triangles...
Therefore,
ab/ad=ac/ae
(ad+bd)/ad=ac/ae. .....(1)
now, putting values of ad,bd & ac in (1)
=> {(5+7)/5}={18/AE}
=> AE=(18x5)/12
i.e;
AE=7.5
EC=7.5
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