in a triangle ABC if 3A=4B=6C.find angle A B AND C
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Answered by
114
A=x/3 B=x/4 c=x/6
A+B+C=180
x/3+x/4+x/6=180
9x/12=180
x=240
a=80 B=60 C=40
A+B+C=180
x/3+x/4+x/6=180
9x/12=180
x=240
a=80 B=60 C=40
Answered by
45
Hey there!
Let angle A be equal to x,
Now,
3A = 4B
3/4x = B
At the same time,
3A = 6C
3/6A = C
1/2x = C
We know that, According to angle sum property, Sum of angles in a triangle is equal to 180°
So,
A + B + C = 180°
x + 3/4x + 1/2x = 180
x ( 1 + 3/4 + 1/2 ) = 180
x ( 4 + 3 + 2 / 4 ) = 180
x ( 9/4) = 180
x = 20 * 4
x = 80 .
Now, Angle A = 80°
B = 3/4 ( 80 ) = 60°
C = 1/2 ( 80 ) = 40°
Therefore the Angles of a triangle are 80° ,60°, 40° respectively
Let angle A be equal to x,
Now,
3A = 4B
3/4x = B
At the same time,
3A = 6C
3/6A = C
1/2x = C
We know that, According to angle sum property, Sum of angles in a triangle is equal to 180°
So,
A + B + C = 180°
x + 3/4x + 1/2x = 180
x ( 1 + 3/4 + 1/2 ) = 180
x ( 4 + 3 + 2 / 4 ) = 180
x ( 9/4) = 180
x = 20 * 4
x = 80 .
Now, Angle A = 80°
B = 3/4 ( 80 ) = 60°
C = 1/2 ( 80 ) = 40°
Therefore the Angles of a triangle are 80° ,60°, 40° respectively
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