In a triangle abc if angle a + b = 110 and angle b + c = 132, then find angle a b c
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a = 110 - B
c = b- 132
a+b + c = 180
110 - b +b +b - 132 = 180
-22+b = 180
b = 180 +22
b = 202
c = b- 132
a+b + c = 180
110 - b +b +b - 132 = 180
-22+b = 180
b = 180 +22
b = 202
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