Question

in a triangle abc is a=45;b=3x+16;c=68..find X

Answer 1

☆ Given:-
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∠1 of a triangle = a = 45

∠2 of a triangle = b = 3x + 16

∠3 of a triangle = c = 68
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☆ Calculation:-
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We know that, ∠1 + ∠2 + ∠3 = 180° (Angle sum property of triangle)

45 + 3x + 16 + 68 = 180

3x + 129 = 180

3x = 180 - 129

3x = 51

x = 51/3

x = 17° Ans.
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∠2 = b = 3x + 16

= 3 * 17 + 16

= 51 + 16

= 67°
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Ans.) X = 17°.