Question

In a triangle the sum of two angle is one third part of third angle if their difference is 5degree.then find all angles

Answer 1

let x and y be the angles of given triangle and z be the third angle .A.T.Q; x+ y =1/3 of z and x+y+z=180° thus z/3+z =180° and 4z=180×3 now z=45×3=135°now we can find x and y ; x+y=45° and x-y=5° by elimination method 2x=50°and x=25° thus y=20°