in a triangleABC, ad is the altitude of the triangle find AB+BC+CA>2AD
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Answer:
AB=90°BC=90°CA=90°=270°
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given: ABC is a triangle.
AD is an altitude.
RTP:AB+BC+AC>2AD
PROOF: in triABD,
AB+BD>AD(sum of any two sides of a tri. are greater than the third side)......i
In triACD,
DC+Ac>AD......... ii
Adding i and ii ,we get
AB+(BD+DC)+AC>AD+AD
AB+BC+CA>2AD
HENCE,PROVED
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