Question

In a TV picture tube, electrons are ejected from the cathode with negligible speed and they attain a velocity of 5 × 106 m/s in travelling one centimetre. Assuming straight-line motion, find the constant force exerted on the electrons. The mass of an electron is 9.1 × 10−31 kg

Answer 1

Given :

Initial velocity of the electrons is negligible  u = 0m/s

Final velocity of the electrons v = 5 × 10⁶ m/s

Distance travelled by the electrons,

s = 1 cm = 1 × 10⁻² m

∴ Acceleration, =a=v²-u²/2 S

⇒a=(5×10⁶)²-0²/2×1×10⁻³

=25×10¹²/2×10⁻²

⇒a=12.5×10¹⁴m/s²

So, force on the electrons, F = ma

⇒ F = 9.1 × 10⁻³¹ × 12.5 × 10⁻¹⁴

= 1.1 × 10⁻¹⁵ N

Answer 2

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