In a two digit no. , the unit digit is 1 more than twice the tens digit. If the order of the digits is reversed, the new no. is 36 mor than the given no. Find the number.
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Let the tens place digit be a
Unit place digit = 2a+1
No. = 10(a) + (2a+1)
= 10a+2a+1
= 12a + 1
Reversed no. = 10(2a+1)+ a
= 20a+10 + a
= 21a + 10
According to question
Original no. +36 = Reversed no.
=> 12a+1 + 36 = 21a + 10
=> 21a-12a = 37 - 10
=> 9a = 27
=> a = 3
Unit place digit = 3
Tens place digit = 7
Required no. = 37
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