Question

In a two digit number unit place digit is 3 more than the tens place digit. If sum of digits is 18 less than the original number than what is the product of digits (ଅଙ୍କଦ୍ଵୟର ଗୁଣଫଳ କେତେ )?
10
15
20
25
Option 5​

Answer 1

Step-by-step explanation:

Let the ten's digit be x and unit's digit be y.

Then, x + y = 15 and x - y = 3 or y - x = 3.

Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.

Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.

So, the number is either 96 or 69.

Hence, the number cannot be determined.

Answer 2

Step-by-step explanation:

Let the unit digit number is x

Tens digit number is y

The number is of the for 10 y + x

It is given number in the tens place = 3 times the number in the unit place

Therefore y = 3 x

The reversed number is 10 x + y

10 y + x + 10 x + y = 88

11 x + 11 y = 88 [dividing both sides by 11]

x + y = 8

x + 3 x = 8 [ since y= 3 x]

4 x = 8

x = 2

y = 3 x = 6

The two digit number is 10(6) + 2 = 62

Reversed number = 26

Verification Number in the tens place = 3 x number in the unit place

6 = 3(2)

sum of the number and the reversed = 88

62 + 26 = 88