In ABC, AB = 51 cm, BC = 52 cm and CA = 101 cm, then find the area of ABC (using heron's formula)
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Answered by
4
Step-by-step explanation:
s=51+52+101÷2
s= 102
area=(102-51)(102-52)(102-101)
= 51 × 50 × 1
= 51 × 5×10 × 1
Answered by
2
Step-by-step explanation:
s = 51+52+101 / 2
s = 204 / 2
s = 102
Area of traingle = √ s ( s - a ) ( s - b ) ( s - c )
= √ 102 ( 102-51 ) ( 102-52 )
( 102-101 )
= √ 102 x 51 x 50 x 1
= √ 260100
= 510 cm^2
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