Question

In ABC, AB = 51 cm, BC = 52 cm and CA = 101 cm, then find the area of ABC (using heron's formula)​

Answer 1

Step-by-step explanation:

s=51+52+101÷2

s= 102

area=(102-51)(102-52)(102-101)

= 51 × 50 × 1

= 51 × 5×10 × 1

Answer 2

Step-by-step explanation:

s = 51+52+101 / 2

s = 204 / 2

s = 102

Area of traingle = √ s ( s - a ) ( s - b ) ( s - c )

= √ 102 ( 102-51 ) ( 102-52 )

( 102-101 )

= √ 102 x 51 x 50 x 1

= √ 260100

= 510 cm^2